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oracle sql select语句的使用方法

作者:不详 来源:网络 发布时间: 2014-08-25 22:58 点击:
select格式: SELECT [ ALL | DISTINCT ] 字段表达式1[,字段表达式2[,] FROM 表名1,表名2[,] [WHERE 筛选择条件表达式] [GROUP BY 分组表达式 [HAVING分组条件表达式]] [ORDER BY 字段[ASC | DESC]] 语句说明: []方括号为可选项 [GROUP BY 分组表达式 [HAVING分组条

oracle sql select语句的使用方法

  select格式:

  SELECT [ ALL | DISTINCT ] <字段表达式1[,<字段表达式2[,…]

  FROM <表名1>,<表名2>[,…]

  [WHERE <筛选择条件表达式>]

  [GROUP BY <分组表达式> [HAVING<分组条件表达式>]]

  [ORDER BY <字段>[ASC | DESC]]

  语句说明:

  []方括号为可选项

  [GROUP BY <分组表达式> [HAVING<分组条件表达式>]]

  指将结果按<分组表达式>的值进行分组,该值相等的记录为一组,带【HAVING】

  短语则只有满足指定条件的组才会输出。

  [ORDER BY <字段>[ASC | DESC]]

  显示结果要按<字段>值升序或降序进行排序

  练习:

  1:表hkb_test_sore取出成绩sore前5名的记录,

  2:取第5名的记录

  1,答案select a.sore_id, a.sore

  from (select * from hkb_test_sore order by sore desc) a

  where rownum <=5

  2,答案select a.sore_id, a.sore

  from (select * from hkb_test_sore order by sore desc) a

  where rownum <=5

  minus

  select a.sore_id, a.sore

  from (select * from hkb_test_sore order by sore desc) a

  where rownum <=4;

  3:查询两个分数一样的记录

  select *

  from hkb_test_sore a

  where a.sore = (select sore

  from hkb_test_sore a

  group by a.sore

  having count(a.sore) = 2);

  union,union all,intersect,minus的区别:

  SQL> select * from hkb_test2;

  X Y

  ---- -----

  a 1

  b 2

  c 3

  g 4

  SQL> select * from hkb_test3;

  X Y

  ---- -----

  a 1

  b 2

  e 3

  f 4

  SQL> select * from hkb_test2;

  X Y

  ---- -----

  a 1

  b 2

  c 3

  g 4

  SQL> select * from hkb_test3;

  X Y

  ---- -----

  a 1

  b 2

  e 3

  f 4

  SQL> select * from hkb_test2

  2 union

  3 select * from hkb_test3;

  X Y

  ---- -----

  a 1

  b 2

  c 3

  e 3

  f 4

  g 4

  6 rows selected

  SQL> select * from hkb_test2

  2 union all

  3 select * from hkb_test3;

  X Y

  ---- -----

  a 1

  b 2

  c 3

  g 4

  a 1

  b 2

  e 3

  f 4

  8 rows selected

  SQL> select * from hkb_test2

  2 intersect

  3 select * from hkb_test3;

  X Y

  ---- -----

  a 1

  b 2

  SQL> select * from hkb_test2

  2 minus

  3 select * from hkb_test3;

  X Y

  ---- -----

  c 3

  g 4

  综合上面实例看个完整的实例

  SQL>

  SQL>

  SQL> -- create demo table

  SQL> create table Employee(

  2 ID VARCHAR2(4 BYTE) NOT NULL primary key,

  3 First_Name VARCHAR2(10 BYTE),

  4 Last_Name VARCHAR2(10 BYTE),

  5 Start_Date DATE,

  6 End_Date DATE,

  7 Salary Number(8,2),

  8 City VARCHAR2(10 BYTE),

  9 Description VARCHAR2(15 BYTE)

  10 )

  11 /

  Table created.

  SQL>

  SQL> -- prepare data

  SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

  2 values ('01','Jason', 'Martin', to_date('19960725','YYYYMMDD'), to_date('20060725','YYYYMMDD'), 1234.56, 'Toronto', 'Programmer')

  3 /

  1 row created.

  SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

  2 values('02','Alison', 'Mathews', to_date('19760321','YYYYMMDD'), to_date('19860221','YYYYMMDD'), 6661.78, 'Vancouver','Tester')

  3 /

  1 row created.

  SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

  2 values('03','James', 'Smith', to_date('19781212','YYYYMMDD'), to_date('19900315','YYYYMMDD'), 6544.78, 'Vancouver','Tester')

  3 /

  1 row created.

  SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

  2 values('04','Celia', 'Rice', to_date('19821024','YYYYMMDD'), to_date('19990421','YYYYMMDD'), 2344.78, 'Vancouver','Manager')

  3 /

  1 row created.

  SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

  2 values('05','Robert', 'Black', to_date('19840115','YYYYMMDD'), to_date('19980808','YYYYMMDD'), 2334.78, 'Vancouver','Tester')

  3 /

  1 row created.

  SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

  2 values('06','Linda', 'Green', to_date('19870730','YYYYMMDD'), to_date('19960104','YYYYMMDD'), 4322.78,'New York', 'Tester')

  3 /

  1 row created.

  SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

  2 values('07','David', 'Larry', to_date('19901231','YYYYMMDD'), to_date('19980212','YYYYMMDD'), 7897.78,'New York', 'Manager')

  3 /

  1 row created.

  SQL> insert into Employee(ID, First_Name, Last_Name, Start_Date, End_Date, Salary, City, Description)

  2 values('08','James', 'Cat', to_date('19960917','YYYYMMDD'), to_date('20020415','YYYYMMDD'), 1232.78,'Vancouver', 'Tester')

  3 /

  1 row created.

  SQL>

  SQL>

  SQL>

  SQL> -- display data in the table

  SQL> select * from Employee

  2 /

  ID FIRST_NAME LAST_NAME START_DAT END_DATE SALARY CITY DESCRIPTION

  ---- -------------------- -------------------- --------- --------- ---------- ---------- ---------------

  01 Jason Martin 25-JUL-96 25-JUL-06 1234.56 Toronto Programmer

  02 Alison Mathews 21-MAR-76 21-FEB-86 6661.78 Vancouver Tester

  03 James Smith 12-DEC-78 15-MAR-90 6544.78 Vancouver Tester

  04 Celia Rice 24-OCT-82 21-APR-99 2344.78 Vancouver Manager

  05 Robert Black 15-JAN-84 08-AUG-98 2334.78 Vancouver Tester

  06 Linda Green 30-JUL-87 04-JAN-96 4322.78 New York Tester

  07 David Larry 31-DEC-90 12-FEB-98 7897.78 New York Manager

  08 James Cat 17-SEP-96 15-APR-02 1232.78 Vancouver Tester

  8 rows selected.

  SQL>

  SQL>

  SQL> SELECT id, first_name, last_name FROM employee

  2 /

  ID FIRST_NAME LAST_NAME

  ---- -------------------- --------------------

  01 Jason Martin

  02 Alison Mathews

  03 James Smith

  04 Celia Rice

  05 Robert Black

  06 Linda Green

  07 David Larry

  08 James Cat

  8 rows selected.

  在ORACLE中实现SELECT TOP N的方法

  1.在ORACLE中实现SELECT TOP N

  由于ORACLE不支持SELECT TOP语句,所以在ORACLE中经常是用ORDER BY跟ROWNUM的组合来实现SELECT TOP N的查询。

  简单地说,实现方法如下所示:

  SELECT列名1...列名nFROM

  (SELECT列名1...列名nFROM 表名 ORDER BY 列名1...列名n)

  WHERE ROWNUM <= N(抽出记录数)

  ORDER BY ROWNUM ASC

  下面举个例子简单说明一下。

  顾客表customer(id,name)有如下数据:

  ID NAME

  01 first

  02 Second

  03 third

  04 forth

  05 fifth

  06 sixth

  07 seventh

  08 eighth

  09 ninth

  10 tenth

  11 last

  则按NAME的字母顺抽出前三个顾客的SQL语句如下所示:

  SELECT * FROM

  (SELECT * FROM CUSTOMER ORDER BY NAME)

  WHERE ROWNUM <= 3

  ORDER BY ROWNUM ASC

  输出结果为:

  ID NAME

  08 eighth

  05 fifth

  01 first

  2.在TOP N纪录中抽出第M(M <= N)条记录

  在得到了TOP N的数据之后,为了抽出这N条记录中的第M条记录,我们可以考虑从ROWNUM着手。我们知道,ROWNUM是记录表中数据编号的一个隐藏子段,所以可以在得到TOP N条记录的时候同时抽出记录的ROWNUM,然后再从这N条记录中抽取记录编号为M的记录,即使我们希望得到的结果。

  从上面的分析可以很容易得到下面的SQL语句。

  SELECT 列名1...列名n FROM

  (

  SELECT ROWNUM RECNO, 列名1...列名nFROM

  (SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

  WHERE ROWNUM <= N(抽出记录数)

  ORDER BY ROWNUM ASC

  )

  WHERE RECNO = M(M <= N)

  同样以上表的数据为基础,那么得到以NAME的字母顺排序的第二个顾客的信息的SQL语句应该这样写:

  SELECT ID, NAME FROM

  (

  SELECT ROWNUM RECNO, ID, NAME FROM

  (SELECT * FROM CUSTOMER ORDER BY NAME)

  WHERE ROWNUM <= 3

  ORDER BY ROWNUM ASC )

  WHERE RECNO = 2

  结果则为:

  ID NAME

  05 fifth

  3.抽出按某种方式排序的记录集中的第N条记录

  在2的说明中,当M = N的时候,即为我们的标题讲的结果。实际上,2的做法在里面N>M的部分的数据是基本上不会用到的,我们仅仅是为了说明方便而采用。

  如上所述,则SQL语句应为:

  SELECT 列名1...列名n FROM

  (

  SELECT ROWNUM RECNO, 列名1...列名nFROM

  (SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

  WHERE ROWNUM <= N(抽出记录数)

  ORDER BY ROWNUM ASC

  )

  WHERE RECNO = N

  那么,2中的例子的SQL语句则为:

  SELECT ID, NAME FROM

  (

  SELECT ROWNUM RECNO, ID, NAME FROM

  (SELECT * FROM CUSTOMER ORDER BY NAME)

  WHERE ROWNUM <= 2

  ORDER BY ROWNUM ASC

  )

  WHERE RECNO = 2

  结果为:

  ID NAME

  05 fifth

  4.抽出按某种方式排序的记录集中的第M条记录开始的X条记录

  3里所讲得仅仅是抽取一条记录的情况,当我们需要抽取多条记录的时候,此时在2中的N的取值应该是在N >= (M + X - 1)这个范围内,当让最经济的取值就是取等好的时候了的时候了。当然最后的抽取条件也不是RECNO = N了,应该是RECNO BETWEEN M AND (M + X - 1)了,所以随之而来的SQL语句则为:

  SELECT 列名1...列名n FROM

  (

  SELECT ROWNUM RECNO, 列名1...列名nFROM

  (

  SELECT 列名1...列名n FROM 表名 ORDER BY 列名1...列名n)

  WHERE ROWNUM <= N (N >= (M + X - 1))

  ORDER BY ROWNUM ASC

  )

  WHERE RECNO BETWEEN M AND (M + X - 1)

  同样以上面的数据为例,则抽取NAME的字母顺的第2条记录开始的3条记录的SQL语句为:

  SELECT ID, NAME FROM

  (

  SELECT ROWNUM RECNO, ID, NAME FROM

  (SELECT * FROM CUSTOMER ORDER BY NAME)

  WHERE ROWNUM <= (2 + 3 - 1)

  ORDER BY ROWNUM ASC

  )

  WHERE RECNO BETWEEN 2 AND (2 + 3 - 1)

         :更多精彩文章请关注三联编程教程栏目。
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