SQL字符串转换为数组
/*
一、按指定符号分割字符串，返回分割后的元素个数，方法很简单，就是看字符串中存在多少个分隔符号，然后再加一，就是要求的结果。
-----rtrim(@str)去掉 @str右边的字符 ltrim(@str)去掉左边的字符 ltrim(rtrim(@str))去掉左右空格
-------charindex 在变量@str中@split的index即索引值
create function Get_StrArrayLength
(
@str varchar(5000), --要分割的字符串
@split varchar(10) --分隔符号
)
returns int
as
begin
declare @location int
declare @start int
declare @length int
set @str=ltrim(rtrim(@str))
set @location=charindex(@split,@str)
set @length=1
while @location<>0
begin
set @start=@location+1
set @location=charindex(@split,@str,@start)
set @length=@length+1
end
return @length
end
二、按指定符号分割字符串，返回分割后指定索引的第几个元素，象数组一样方便
create function Get_StrArrayStrOfIndex
(
@str varchar(5000), --要分割的字符串
@split varchar(10), --分隔符号
@index int --取第几个元素
)
returns varchar(5000)
as
begin
declare @location int
declare @start int
declare @next int
declare @seed int
set @str=ltrim(rtrim(@str))
set @start=1
set @next=1
set @seed=len(@split)
set @location=charindex(@split,@str)
while @location<>0 and @index>@next
begin
set @start=@location+@seed
set @location=charindex(@split,@str,@start)
set @next=@next+1
end
if @location =0 select @location =len(@str)+1
return substring(@str,@start,@location-@start)
end
调用示例
--==================================
declare @str varchar(5000)
set @str='1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48'
print dbo.Get_StrArrayLength(@str,',')
declare @next int
declare @s varchar(100)
set @next=1
while @next<=dbo.Get_StrArrayLength(@str,',')
begin
print dbo.Get_StrArrayStrOfIndex(@str,',',@next) ----输出数组中的值
set @next=@next+1
end
--==================================
四、检查一个元素是否在数组中
Create function CheckStrInArr(@s as varchar(50),@sArr as varchar(5000)) returns int
as
begin
declare @str varchar(5000)
set @str=@sArr
declare @next int
declare @ret int
set @ret=0
set @next=1
while @next<=dbo.Get_StrArrayLength(@str,',')
begin
if dbo.Get_StrArrayStrOfIndex(@str,',',@next)=@s
begin
set @ret=1;
end
set @next=@next+1
end
return @ret
end
-- =========调用失利========
declare @a int
set @a=dbo.CheckStrInArr('8','2,3,5,8')
select @a
-- =========调用失利========
五 检查一个元素是否与数组中的相匹配
--select dbo.CheckStrLikeInArr(2,'d','sde,df,aad,d,fgsa,fgd')
Create function CheckStrLikeInArr
(
@liketype int=0, --like类型(0为为@keyword%,2为) 一般只用0
@keyword as varchar(50), --要检查的关键字
@sArr as varchar(5000) --数组
)
returns nvarchar(max)
as
begin
declare @str varchar(5000)
set @str=@sArr
declare @start int
declare @result nvarchar(max)
set @result=''
set @start=1
declare @temp nvarchar(20);
while @start<=dbo.Get_StrArrayLength(@str,',')
begin
if @liketype=0
begin
set @temp=dbo.Get_StrArrayStrOfIndex(@str,',',@start);
if @temp like '%'+ @keyword+'%'
begin
set @result=@result+ @temp +',';
end
set @start=@start+1
end
else if @liketype=1
begin
if dbo.Get_StrArrayStrOfIndex(@str,',',@start) like ''+ @keyword +'%'
begin
set @result=dbo.Get_StrArrayStrOfIndex(@str, ',' , @start)+',';
end
set @start=@start+1
end
else if @liketype=2
begin
if dbo.Get_StrArrayStrOfIndex( @str, ',' , @start) like '%'+ @keyword+''
begin
set @result=dbo.Get_StrArrayStrOfIndex(@str, ',' , @start)+',';
end
set @start=@start+1
end
end
return @result
-- return cast(dbo.Get_StrArrayLength(@result,',')as nvarchar(2000))
end